Base | Representation |
---|---|
bin | 101111011000000100110… |
… | …1101100101000110101100 |
3 | 212001110220000110211000011 |
4 | 1132300021231211012230 |
5 | 1323140202320123030 |
6 | 21503133143343004 |
7 | 1241266624252513 |
oct | 136601155450654 |
9 | 25043800424004 |
10 | 6511333364140 |
11 | 2090493a300a0 |
12 | 891b34451a64 |
13 | 3830294b52a7 |
14 | 18721629d67a |
15 | b4594a59b2a |
hex | 5ec09b651ac |
6511333364140 has 48 divisors (see below), whose sum is σ = 14917584407040. Its totient is φ = 2367644633280.
The previous prime is 6511333364131. The next prime is 6511333364141. The reversal of 6511333364140 is 414633331156.
It is a junction number, because it is equal to n+sod(n) for n = 6511333364093 and 6511333364102.
It is not an unprimeable number, because it can be changed into a prime (6511333364141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3986941 + ... + 5377579.
It is an arithmetic number, because the mean of its divisors is an integer number (310783008480).
Almost surely, 26511333364140 is an apocalyptic number.
It is an amenable number.
6511333364140 is an abundant number, since it is smaller than the sum of its proper divisors (8406251042900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
6511333364140 is a wasteful number, since it uses less digits than its factorization.
6511333364140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1411942 (or 1411940 counting only the distinct ones).
The product of its (nonzero) digits is 233280, while the sum is 40.
Adding to 6511333364140 its reverse (414633331156), we get a palindrome (6925966695296).
The spelling of 6511333364140 in words is "six trillion, five hundred eleven billion, three hundred thirty-three million, three hundred sixty-four thousand, one hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •