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651314012101 is a prime number
BaseRepresentation
bin10010111101001010101…
…01110001111111000101
32022021011012012221211221
421132211111301333011
541132342341341401
61215113131400341
765025111520564
oct11364525617705
92267135187757
10651314012101
11231247864365
12a628b8b30b1
13495599ccc8c
1423749301bdb
1511e1ec6e7a1
hex97a5571fc5

651314012101 has 2 divisors, whose sum is σ = 651314012102. Its totient is φ = 651314012100.

The previous prime is 651314012087. The next prime is 651314012183. The reversal of 651314012101 is 101210413156.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 396012197025 + 255301815076 = 629295^2 + 505274^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-651314012101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (651314312101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325657006050 + 325657006051.

It is an arithmetic number, because the mean of its divisors is an integer number (325657006051).

Almost surely, 2651314012101 is an apocalyptic number.

It is an amenable number.

651314012101 is a deficient number, since it is larger than the sum of its proper divisors (1).

651314012101 is an equidigital number, since it uses as much as digits as its factorization.

651314012101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 651314012101 its reverse (101210413156), we get a palindrome (752524425257).

The spelling of 651314012101 in words is "six hundred fifty-one billion, three hundred fourteen million, twelve thousand, one hundred one".