Base | Representation |
---|---|
bin | 11101100111101010001001… |
… | …01010100011110011110101 |
3 | 22112121210002112002002101220 |
4 | 32303311010222203303311 |
5 | 32014130102222120003 |
6 | 350310144255340553 |
7 | 16501541304665532 |
oct | 1663650452436365 |
9 | 275553075062356 |
10 | 65134331051253 |
11 | 198323509146a2 |
12 | 737b577821759 |
13 | 2a461aabb90a9 |
14 | 1212738875d89 |
15 | 77e4604a2353 |
hex | 3b3d44aa3cf5 |
65134331051253 has 32 divisors (see below), whose sum is σ = 97525354620672. Its totient is φ = 38450856576000.
The previous prime is 65134331051227. The next prime is 65134331051291. The reversal of 65134331051253 is 35215013343156.
It is not a de Polignac number, because 65134331051253 - 26 = 65134331051189 is a prime.
It is a super-2 number, since 2×651343310512532 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (65134331051203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 455075898 + ... + 455219003.
It is an arithmetic number, because the mean of its divisors is an integer number (3047667331896).
Almost surely, 265134331051253 is an apocalyptic number.
It is an amenable number.
65134331051253 is a deficient number, since it is larger than the sum of its proper divisors (32391023569419).
65134331051253 is a wasteful number, since it uses less digits than its factorization.
65134331051253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 910295005.
The product of its (nonzero) digits is 486000, while the sum is 42.
The spelling of 65134331051253 in words is "sixty-five trillion, one hundred thirty-four billion, three hundred thirty-one million, fifty-one thousand, two hundred fifty-three".
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