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65149703 is a prime number
BaseRepresentation
bin1111100010000…
…1101100000111
311112120221120222
43320201230013
5113134242303
610244214555
71420522553
oct370415407
9145527528
1065149703
1133858a33
121999a45b
1310660c28
14891c863
155abd938
hex3e21b07

65149703 has 2 divisors, whose sum is σ = 65149704. Its totient is φ = 65149702.

The previous prime is 65149657. The next prime is 65149723. The reversal of 65149703 is 30794156.

65149703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 65149703 - 210 = 65148679 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65149723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32574851 + 32574852.

It is an arithmetic number, because the mean of its divisors is an integer number (32574852).

Almost surely, 265149703 is an apocalyptic number.

65149703 is a deficient number, since it is larger than the sum of its proper divisors (1).

65149703 is an equidigital number, since it uses as much as digits as its factorization.

65149703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22680, while the sum is 35.

The square root of 65149703 is about 8071.5365947259. The cubic root of 65149703 is about 402.3810133994.

The spelling of 65149703 in words is "sixty-five million, one hundred forty-nine thousand, seven hundred three".