654021131 has 2 divisors, whose sum is σ = 654021132. Its totient is φ = 654021130.

The previous prime is 654021101. The next prime is 654021133. The reversal of 654021131 is 131120456.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-654021131 is a prime.

It is a super-2 number, since 2×654021131² = 855487279589038322, which contains 22 as substring.

Together with 654021133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 654021097 and 654021106.

It is not a weakly prime, because it can be changed into another prime (654021133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327010565 + 327010566.

It is an arithmetic number, because the mean of its divisors is an integer number (327010566).

Almost surely, 2^654021131 is an apocalyptic number.

654021131 is a deficient number, since it is larger than the sum of its proper divisors (1).

654021131 is an equidigital number, since it uses as much as digits as its factorization.

654021131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 654021131 is about 25573.8368454950. The cubic root of 654021131 is about 868.0217220632.

Adding to 654021131 its reverse (131120456), we get a palindrome (785141587).

The spelling of 654021131 in words is "six hundred fifty-four million, twenty-one thousand, one hundred thirty-one".