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6553147121 is a prime number
BaseRepresentation
bin1100001101001100…
…10001011011110001
3121220200220100212122
412012212101123301
5101410101201441
63002132404025
7321251555123
oct60646213361
917820810778
106553147121
112863098474
12132a776615
1380586b861
1446247b213
1528549d34b
hex1869916f1

6553147121 has 2 divisors, whose sum is σ = 6553147122. Its totient is φ = 6553147120.

The previous prime is 6553147087. The next prime is 6553147123. The reversal of 6553147121 is 1217413556.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3473452096 + 3079695025 = 58936^2 + 55495^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6553147121 is a prime.

It is a super-3 number, since 3×65531471213 (a number of 30 digits) contains 333 as substring.

Together with 6553147123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (6553147123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276573560 + 3276573561.

It is an arithmetic number, because the mean of its divisors is an integer number (3276573561).

Almost surely, 26553147121 is an apocalyptic number.

It is an amenable number.

6553147121 is a deficient number, since it is larger than the sum of its proper divisors (1).

6553147121 is an equidigital number, since it uses as much as digits as its factorization.

6553147121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25200, while the sum is 35.

The square root of 6553147121 is about 80951.5109247505. The cubic root of 6553147121 is about 1871.3282451407.

The spelling of 6553147121 in words is "six billion, five hundred fifty-three million, one hundred forty-seven thousand, one hundred twenty-one".