Base | Representation |
---|---|
bin | 11110000100000101111101… |
… | …01010110000101101010111 |
3 | 22200002011220122022111200212 |
4 | 33002002332222300231113 |
5 | 32131132003342010011 |
6 | 352335043411400035 |
7 | 16632246344536121 |
oct | 1702027652605527 |
9 | 280064818274625 |
10 | 66111335500631 |
11 | 1a079729409aa3 |
12 | 74b89a05b301b |
13 | 2ab736ccc2a35 |
14 | 1247b3cc2c211 |
15 | 799a92ed708b |
hex | 3c20beab0b57 |
66111335500631 has 2 divisors, whose sum is σ = 66111335500632. Its totient is φ = 66111335500630.
The previous prime is 66111335500559. The next prime is 66111335500633. The reversal of 66111335500631 is 13600553311166.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 66111335500631 - 214 = 66111335484247 is a prime.
It is a super-2 number, since 2×661113355006312 (a number of 28 digits) contains 22 as substring.
Together with 66111335500633, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (66111335500633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33055667750315 + 33055667750316.
It is an arithmetic number, because the mean of its divisors is an integer number (33055667750316).
Almost surely, 266111335500631 is an apocalyptic number.
66111335500631 is a deficient number, since it is larger than the sum of its proper divisors (1).
66111335500631 is an equidigital number, since it uses as much as digits as its factorization.
66111335500631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 41.
Adding to 66111335500631 its reverse (13600553311166), we get a palindrome (79711888811797).
The spelling of 66111335500631 in words is "sixty-six trillion, one hundred eleven billion, three hundred thirty-five million, five hundred thousand, six hundred thirty-one".
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