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66111335500631 is a prime number
BaseRepresentation
bin11110000100000101111101…
…01010110000101101010111
322200002011220122022111200212
433002002332222300231113
532131132003342010011
6352335043411400035
716632246344536121
oct1702027652605527
9280064818274625
1066111335500631
111a079729409aa3
1274b89a05b301b
132ab736ccc2a35
141247b3cc2c211
15799a92ed708b
hex3c20beab0b57

66111335500631 has 2 divisors, whose sum is σ = 66111335500632. Its totient is φ = 66111335500630.

The previous prime is 66111335500559. The next prime is 66111335500633. The reversal of 66111335500631 is 13600553311166.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 66111335500631 - 214 = 66111335484247 is a prime.

It is a super-2 number, since 2×661113355006312 (a number of 28 digits) contains 22 as substring.

Together with 66111335500633, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (66111335500633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33055667750315 + 33055667750316.

It is an arithmetic number, because the mean of its divisors is an integer number (33055667750316).

Almost surely, 266111335500631 is an apocalyptic number.

66111335500631 is a deficient number, since it is larger than the sum of its proper divisors (1).

66111335500631 is an equidigital number, since it uses as much as digits as its factorization.

66111335500631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 41.

Adding to 66111335500631 its reverse (13600553311166), we get a palindrome (79711888811797).

The spelling of 66111335500631 in words is "sixty-six trillion, one hundred eleven billion, three hundred thirty-five million, five hundred thousand, six hundred thirty-one".