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666150126032351 is a prime number
BaseRepresentation
bin1001011101110111000010100…
…1101000010001010111011111
310020100122022220122102212100002
42113131300221220101113133
51144303200424231013401
610320441050531524515
7260212521060155432
oct22735605150212737
93210568818385302
10666150126032351
1118328a755713614
126286843545973b
13227918c2123bbc
14ba6dba3b91819
1552031608d0a6b
hex25ddc29a115df

666150126032351 has 2 divisors, whose sum is σ = 666150126032352. Its totient is φ = 666150126032350.

The previous prime is 666150126032327. The next prime is 666150126032353. The reversal of 666150126032351 is 153230621051666.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-666150126032351 is a prime.

Together with 666150126032353, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 666150126032296 and 666150126032305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (666150126032353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333075063016175 + 333075063016176.

It is an arithmetic number, because the mean of its divisors is an integer number (333075063016176).

Almost surely, 2666150126032351 is an apocalyptic number.

666150126032351 is a deficient number, since it is larger than the sum of its proper divisors (1).

666150126032351 is an equidigital number, since it uses as much as digits as its factorization.

666150126032351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1166400, while the sum is 47.

The spelling of 666150126032351 in words is "six hundred sixty-six trillion, one hundred fifty billion, one hundred twenty-six million, thirty-two thousand, three hundred fifty-one".