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66734715125789 is a prime number
BaseRepresentation
bin11110010110001111000101…
…11111010100000000011101
322202021202222001001120120222
433023013202333110000131
532221340144033011124
6353533301020251125
720025265311115454
oct1713074277240035
9282252861046528
1066734715125789
111a29a040a10a57
1275997750a0aa5
132b31097568a69
141269d9817db9b
157aadca65125e
hex3cb1e2fd401d

66734715125789 has 2 divisors, whose sum is σ = 66734715125790. Its totient is φ = 66734715125788.

The previous prime is 66734715125747. The next prime is 66734715125791. The reversal of 66734715125789 is 98752151743766.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43207510390564 + 23527204735225 = 6573242^2 + 4850485^2 .

It is a cyclic number.

It is not a de Polignac number, because 66734715125789 - 212 = 66734715121693 is a prime.

It is a super-2 number, since 2×667347151257892 (a number of 28 digits) contains 22 as substring.

Together with 66734715125791, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (66734715125189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33367357562894 + 33367357562895.

It is an arithmetic number, because the mean of its divisors is an integer number (33367357562895).

Almost surely, 266734715125789 is an apocalyptic number.

It is an amenable number.

66734715125789 is a deficient number, since it is larger than the sum of its proper divisors (1).

66734715125789 is an equidigital number, since it uses as much as digits as its factorization.

66734715125789 is an evil number, because the sum of its binary digits is even.

The product of its digits is 533433600, while the sum is 71.

The spelling of 66734715125789 in words is "sixty-six trillion, seven hundred thirty-four billion, seven hundred fifteen million, one hundred twenty-five thousand, seven hundred eighty-nine".