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671113512647 is a prime number
BaseRepresentation
bin10011100010000010111…
…10111000011011000111
32101011021001110210112222
421301001132320123013
541443420024401042
61232145535402555
766325550510144
oct11610136703307
92334231423488
10671113512647
1123968809a156
12aa09668345b
134b3939a7186
14246a6b153cb
15126cd0d32d2
hex9c417b86c7

671113512647 has 2 divisors, whose sum is σ = 671113512648. Its totient is φ = 671113512646.

The previous prime is 671113512623. The next prime is 671113512649. The reversal of 671113512647 is 746215311176.

671113512647 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 671113512647 - 26 = 671113512583 is a prime.

Together with 671113512649, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 671113512598 and 671113512607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (671113512649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335556756323 + 335556756324.

It is an arithmetic number, because the mean of its divisors is an integer number (335556756324).

Almost surely, 2671113512647 is an apocalyptic number.

671113512647 is a deficient number, since it is larger than the sum of its proper divisors (1).

671113512647 is an equidigital number, since it uses as much as digits as its factorization.

671113512647 is an evil number, because the sum of its binary digits is even.

The product of its digits is 211680, while the sum is 44.

The spelling of 671113512647 in words is "six hundred seventy-one billion, one hundred thirteen million, five hundred twelve thousand, six hundred forty-seven".