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671314124433 = 3223771374811
BaseRepresentation
bin10011100010011010111…
…00001001111010010001
32101011210000221221012010
421301031130021322101
541444322403440213
61232221503253133
766333534623151
oct11611534117221
92334700857163
10671314124433
1123978035a817
12aa1318aa1a9
134b3c6416a84
14246c5616761
15126e0a0dac3
hex9c4d709e91

671314124433 has 4 divisors (see below), whose sum is σ = 895085499248. Its totient is φ = 447542749620.

The previous prime is 671314124417. The next prime is 671314124489. The reversal of 671314124433 is 334421413176.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 671314124433 - 24 = 671314124417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 671314124391 and 671314124400.

It is not an unprimeable number, because it can be changed into a prime (671314124933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111885687403 + ... + 111885687408.

It is an arithmetic number, because the mean of its divisors is an integer number (223771374812).

Almost surely, 2671314124433 is an apocalyptic number.

It is an amenable number.

671314124433 is a deficient number, since it is larger than the sum of its proper divisors (223771374815).

671314124433 is a wasteful number, since it uses less digits than its factorization.

671314124433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 223771374814.

The product of its digits is 145152, while the sum is 39.

The spelling of 671314124433 in words is "six hundred seventy-one billion, three hundred fourteen million, one hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 3 223771374811 671314124433