Base | Representation |
---|---|
bin | 111110100001111011… |
… | …100010111111101101 |
3 | 20102022012002221112222 |
4 | 332201323202333231 |
5 | 2100001130013203 |
6 | 50502210005125 |
7 | 4564552134422 |
oct | 764173427755 |
9 | 212265087488 |
10 | 67141251053 |
11 | 26524538738 |
12 | 110195767a5 |
13 | 64400baa26 |
14 | 336d09bd49 |
15 | 1b2e66e038 |
hex | fa1ee2fed |
67141251053 has 2 divisors, whose sum is σ = 67141251054. Its totient is φ = 67141251052.
The previous prime is 67141250993. The next prime is 67141251091. The reversal of 67141251053 is 35015214176.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49098582724 + 18042668329 = 221582^2 + 134323^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-67141251053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (67141256053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33570625526 + 33570625527.
It is an arithmetic number, because the mean of its divisors is an integer number (33570625527).
Almost surely, 267141251053 is an apocalyptic number.
It is an amenable number.
67141251053 is a deficient number, since it is larger than the sum of its proper divisors (1).
67141251053 is an equidigital number, since it uses as much as digits as its factorization.
67141251053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 35.
The spelling of 67141251053 in words is "sixty-seven billion, one hundred forty-one million, two hundred fifty-one thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •