Base | Representation |
---|---|
bin | 111110111111110011… |
… | …101000000000001101 |
3 | 20110121010021120100111 |
4 | 332333303220000031 |
5 | 2102012434202033 |
6 | 51024033200021 |
7 | 4613146454155 |
oct | 767763500015 |
9 | 213533246314 |
10 | 67642490893 |
11 | 2676147163a |
12 | 11139400011 |
13 | 64bcbb8253 |
14 | 33b9897765 |
15 | 1b5d67e7cd |
hex | fbfce800d |
67642490893 has 2 divisors, whose sum is σ = 67642490894. Its totient is φ = 67642490892.
The previous prime is 67642490837. The next prime is 67642490911. The reversal of 67642490893 is 39809424676.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51548523849 + 16093967044 = 227043^2 + 126862^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-67642490893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (67642490813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33821245446 + 33821245447.
It is an arithmetic number, because the mean of its divisors is an integer number (33821245447).
Almost surely, 267642490893 is an apocalyptic number.
It is an amenable number.
67642490893 is a deficient number, since it is larger than the sum of its proper divisors (1).
67642490893 is an equidigital number, since it uses as much as digits as its factorization.
67642490893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15676416, while the sum is 58.
The spelling of 67642490893 in words is "sixty-seven billion, six hundred forty-two million, four hundred ninety thousand, eight hundred ninety-three".
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