Base | Representation |
---|---|
bin | 111111010101111010… |
… | …011100100011001101 |
3 | 20111112222011120110102 |
4 | 333111322130203031 |
5 | 2103242411041431 |
6 | 51124522420445 |
7 | 4625302113011 |
oct | 772572344315 |
9 | 214488146412 |
10 | 68013377741 |
11 | 269318623a1 |
12 | 11221661725 |
13 | 654b9a541a |
14 | 3412c40541 |
15 | 1b80ee1dcb |
hex | fd5e9c8cd |
68013377741 has 2 divisors, whose sum is σ = 68013377742. Its totient is φ = 68013377740.
The previous prime is 68013377647. The next prime is 68013377743. The reversal of 68013377741 is 14777331086.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62314637641 + 5698740100 = 249629^2 + 75490^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-68013377741 is a prime.
Together with 68013377743, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68013377743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34006688870 + 34006688871.
It is an arithmetic number, because the mean of its divisors is an integer number (34006688871).
Almost surely, 268013377741 is an apocalyptic number.
It is an amenable number.
68013377741 is a deficient number, since it is larger than the sum of its proper divisors (1).
68013377741 is an equidigital number, since it uses as much as digits as its factorization.
68013377741 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 592704, while the sum is 47.
The spelling of 68013377741 in words is "sixty-eight billion, thirteen million, three hundred seventy-seven thousand, seven hundred forty-one".
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