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68141113 is a prime number
BaseRepresentation
bin1000000111111…
…00000000111001
311202012221000221
410003330000321
5114421003423
610432300041
71455122065
oct403740071
9152187027
1068141113
1135511477
121a9a1621
131116a6b1
14909aaa5
155eaee5d
hex40fc039

68141113 has 2 divisors, whose sum is σ = 68141114. Its totient is φ = 68141112.

The previous prime is 68141041. The next prime is 68141119. The reversal of 68141113 is 31114186.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61653904 + 6487209 = 7852^2 + 2547^2 .

It is a cyclic number.

It is not a de Polignac number, because 68141113 - 29 = 68140601 is a prime.

It is a super-2 number, since 2×681411132 = 9286422561757538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (68141119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34070556 + 34070557.

It is an arithmetic number, because the mean of its divisors is an integer number (34070557).

Almost surely, 268141113 is an apocalyptic number.

It is an amenable number.

68141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

68141113 is an equidigital number, since it uses as much as digits as its factorization.

68141113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 25.

The square root of 68141113 is about 8254.7630492946. The cubic root of 68141113 is about 408.4476556015.

Adding to 68141113 its reverse (31114186), we get a palindrome (99255299).

The spelling of 68141113 in words is "sixty-eight million, one hundred forty-one thousand, one hundred thirteen".