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683116554149 is a prime number
BaseRepresentation
bin10011111000011001110…
…10110110011110100101
32102022020120022111001122
421330030322312132211
542143010314213044
61241452554303325
7100232156622221
oct11741472663645
92368216274048
10683116554149
11243787538967
12b0486427b45
134c5576651b3
14250c4cc5781
1512b81c54dee
hex9f0ceb67a5

683116554149 has 2 divisors, whose sum is σ = 683116554150. Its totient is φ = 683116554148.

The previous prime is 683116554067. The next prime is 683116554167. The reversal of 683116554149 is 941455611386.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 634300744900 + 48815809249 = 796430^2 + 220943^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-683116554149 is a prime.

It is a super-2 number, since 2×6831165541492 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 683116554149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (683116554749) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341558277074 + 341558277075.

It is an arithmetic number, because the mean of its divisors is an integer number (341558277075).

Almost surely, 2683116554149 is an apocalyptic number.

It is an amenable number.

683116554149 is a deficient number, since it is larger than the sum of its proper divisors (1).

683116554149 is an equidigital number, since it uses as much as digits as its factorization.

683116554149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3110400, while the sum is 53.

The spelling of 683116554149 in words is "six hundred eighty-three billion, one hundred sixteen million, five hundred fifty-four thousand, one hundred forty-nine".