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6834424514903 is a prime number
BaseRepresentation
bin110001101110100001101…
…1100100000100101010111
3220012100211210110211200022
41203131003130200211113
51343433400133434103
622311405152135355
71303525260602336
oct143350334404527
926170753424608
106834424514903
1121a5510513767
12924682b3755b
133a76392389cb
14198b06059d1d
15bcba4531138
hex63743720957

6834424514903 has 2 divisors, whose sum is σ = 6834424514904. Its totient is φ = 6834424514902.

The previous prime is 6834424514887. The next prime is 6834424514921. The reversal of 6834424514903 is 3094154244386.

It is a happy number.

6834424514903 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 6834424514903 - 24 = 6834424514887 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6834424514993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3417212257451 + 3417212257452.

It is an arithmetic number, because the mean of its divisors is an integer number (3417212257452).

Almost surely, 26834424514903 is an apocalyptic number.

6834424514903 is a deficient number, since it is larger than the sum of its proper divisors (1).

6834424514903 is an equidigital number, since it uses as much as digits as its factorization.

6834424514903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9953280, while the sum is 53.

The spelling of 6834424514903 in words is "six trillion, eight hundred thirty-four billion, four hundred twenty-four million, five hundred fourteen thousand, nine hundred three".