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691215139663 is a prime number
BaseRepresentation
bin10100000111011111010…
…00100000001101001111
32110002010222020020212021
422003233220200031033
542311102033432123
61245312335151011
7100636645513546
oct12035750401517
92402128206767
10691215139663
11247162a21044
12b1b66675467
1350248445029
14256526d315d
1512ea7c25c5d
hexa0efa2034f

691215139663 has 2 divisors, whose sum is σ = 691215139664. Its totient is φ = 691215139662.

The previous prime is 691215139631. The next prime is 691215139669. The reversal of 691215139663 is 366931512196.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 691215139663 - 25 = 691215139631 is a prime.

It is a super-4 number, since 4×6912151396634 (a number of 48 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 691215139663.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (691215139669) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 345607569831 + 345607569832.

It is an arithmetic number, because the mean of its divisors is an integer number (345607569832).

Almost surely, 2691215139663 is an apocalyptic number.

691215139663 is a deficient number, since it is larger than the sum of its proper divisors (1).

691215139663 is an equidigital number, since it uses as much as digits as its factorization.

691215139663 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1574640, while the sum is 52.

The spelling of 691215139663 in words is "six hundred ninety-one billion, two hundred fifteen million, one hundred thirty-nine thousand, six hundred sixty-three".