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71000019000089 is a prime number
BaseRepresentation
bin10000001001001011111010…
…111010010101101100011001
3100022101112110101210111111122
4100021023322322111230121
533301231014331000324
6411000543005135025
720645403441624644
oct2011137272255431
9308345411714448
1071000019000089
1120693a36839073
127b6834285a475
133080371bc57aa
1413765c2616a5b
15831d17c61a5e
hex4092fae95b19

71000019000089 has 2 divisors, whose sum is σ = 71000019000090. Its totient is φ = 71000019000088.

The previous prime is 71000019000017. The next prime is 71000019000091. The reversal of 71000019000089 is 98000091000017.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70917367350025 + 82651650064 = 8421245^2 + 287492^2 .

It is an emirp because it is prime and its reverse (98000091000017) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-71000019000089 is a prime.

Together with 71000019000091, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (71000019000289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35500009500044 + 35500009500045.

It is an arithmetic number, because the mean of its divisors is an integer number (35500009500045).

Almost surely, 271000019000089 is an apocalyptic number.

It is an amenable number.

71000019000089 is a deficient number, since it is larger than the sum of its proper divisors (1).

71000019000089 is an equidigital number, since it uses as much as digits as its factorization.

71000019000089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 35.

The spelling of 71000019000089 in words is "seventy-one trillion, nineteen million, eighty-nine", and thus it is an aban number and an uban number.