Base | Representation |
---|---|
bin | 100001000111100110… |
… | …1101111101111000011 |
3 | 20210120122000020002002 |
4 | 1002033031233233003 |
5 | 2131124242101034 |
6 | 52401220014215 |
7 | 5065321624652 |
oct | 1021715575703 |
9 | 223518006062 |
10 | 71122222019 |
11 | 28187705092 |
12 | 1194a83136b |
13 | 6925aa8c54 |
14 | 3629a9b199 |
15 | 1cb3dd5e7e |
hex | 108f36fbc3 |
71122222019 has 2 divisors, whose sum is σ = 71122222020. Its totient is φ = 71122222018.
The previous prime is 71122221943. The next prime is 71122222021. The reversal of 71122222019 is 91022222117.
It is a strong prime.
It is an emirp because it is prime and its reverse (91022222117) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 71122222019 - 28 = 71122221763 is a prime.
It is a super-2 number, since 2×711222220192 (a number of 23 digits) contains 22 as substring.
Together with 71122222021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 71122221982 and 71122222000.
It is not a weakly prime, because it can be changed into another prime (71122227019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35561111009 + 35561111010.
It is an arithmetic number, because the mean of its divisors is an integer number (35561111010).
Almost surely, 271122222019 is an apocalyptic number.
71122222019 is a deficient number, since it is larger than the sum of its proper divisors (1).
71122222019 is an equidigital number, since it uses as much as digits as its factorization.
71122222019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 71122222019 in words is "seventy-one billion, one hundred twenty-two million, two hundred twenty-two thousand, nineteen".
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