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71260130099 is a prime number
BaseRepresentation
bin100001001011101101…
…1110100101100110011
320210221020111200101202
41002113123310230303
52131420043130344
652423023521415
75101615053224
oct1022733645463
9223836450352
1071260130099
1128248538504
1211988a5926b
136948533072
14364011924b
151cc107794e
hex10976f4b33

71260130099 has 2 divisors, whose sum is σ = 71260130100. Its totient is φ = 71260130098.

The previous prime is 71260130009. The next prime is 71260130101. The reversal of 71260130099 is 99003106217.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-71260130099 is a prime.

It is a super-2 number, since 2×712601300992 (a number of 23 digits) contains 22 as substring.

Together with 71260130101, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (71260130009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35630065049 + 35630065050.

It is an arithmetic number, because the mean of its divisors is an integer number (35630065050).

Almost surely, 271260130099 is an apocalyptic number.

71260130099 is a deficient number, since it is larger than the sum of its proper divisors (1).

71260130099 is an equidigital number, since it uses as much as digits as its factorization.

71260130099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 38.

The spelling of 71260130099 in words is "seventy-one billion, two hundred sixty million, one hundred thirty thousand, ninety-nine".