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720442512113 is a prime number
BaseRepresentation
bin10100111101111011011…
…10000101001011110001
32112212120212200121111012
422132331232011023301
543300431240341423
61310544451200305
7103023144212132
oct12367556051361
92485525617435
10720442512113
112585a101a605
12b77628a6095
1352c2571c25c
1426c26299c89
1513b18ad3078
hexa7bdb852f1

720442512113 has 2 divisors, whose sum is σ = 720442512114. Its totient is φ = 720442512112.

The previous prime is 720442512103. The next prime is 720442512187. The reversal of 720442512113 is 311215244027.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 694742254144 + 25700257969 = 833512^2 + 160313^2 .

It is a cyclic number.

It is not a de Polignac number, because 720442512113 - 212 = 720442508017 is a prime.

It is a super-3 number, since 3×7204425121133 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 720442512113.

It is not a weakly prime, because it can be changed into another prime (720442512103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 360221256056 + 360221256057.

It is an arithmetic number, because the mean of its divisors is an integer number (360221256057).

Almost surely, 2720442512113 is an apocalyptic number.

It is an amenable number.

720442512113 is a deficient number, since it is larger than the sum of its proper divisors (1).

720442512113 is an equidigital number, since it uses as much as digits as its factorization.

720442512113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 32.

The spelling of 720442512113 in words is "seven hundred twenty billion, four hundred forty-two million, five hundred twelve thousand, one hundred thirteen".