73000113 has 4 divisors (see below), whose sum is σ = 97333488. Its totient is φ = 48666740.

The previous prime is 73000099. The next prime is 73000153. The reversal of 73000113 is 31100037.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 73000113 - 2¹⁰ = 72999089 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 73000092 and 73000101.

It is not an unprimeable number, because it can be changed into a prime (73000153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12166683 + ... + 12166688.

It is an arithmetic number, because the mean of its divisors is an integer number (24333372).

Almost surely, 2^73000113 is an apocalyptic number.

It is an amenable number.

73000113 is a deficient number, since it is larger than the sum of its proper divisors (24333375).

73000113 is a wasteful number, since it uses less digits than its factorization.

73000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24333374.

The product of its (nonzero) digits is 63, while the sum is 15.

The square root of 73000113 is about 8544.0103581398. The cubic root of 73000113 is about 417.9341352843.

The spelling of 73000113 in words is "seventy-three million, one hundred thirteen", and thus it is an aban number.