Base | Representation |
---|---|
bin | 100010001000111000… |
… | …1111100010111110111 |
3 | 21000020021212112020202 |
4 | 1010101301330113313 |
5 | 2200121030432142 |
6 | 53402430351115 |
7 | 5203521041066 |
oct | 1042161742767 |
9 | 230207775222 |
10 | 73312749047 |
11 | 291011544aa |
12 | 1226035b49b |
13 | 6bb48718a5 |
14 | 37969901dd |
15 | 1d91381032 |
hex | 1111c7c5f7 |
73312749047 has 2 divisors, whose sum is σ = 73312749048. Its totient is φ = 73312749046.
The previous prime is 73312748969. The next prime is 73312749049. The reversal of 73312749047 is 74094721337.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 73312749047 - 210 = 73312748023 is a prime.
Together with 73312749049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 73312748992 and 73312749010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (73312749049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36656374523 + 36656374524.
It is an arithmetic number, because the mean of its divisors is an integer number (36656374524).
Almost surely, 273312749047 is an apocalyptic number.
73312749047 is a deficient number, since it is larger than the sum of its proper divisors (1).
73312749047 is an equidigital number, since it uses as much as digits as its factorization.
73312749047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 889056, while the sum is 47.
The spelling of 73312749047 in words is "seventy-three billion, three hundred twelve million, seven hundred forty-nine thousand, forty-seven".
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