73412625403 has 4 divisors (see below), whose sum is σ = 79059750448. Its totient is φ = 67765500360.

The previous prime is 73412625367. The next prime is 73412625547. The reversal of 73412625403 is 30452621437.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 73412625403 - 2²⁵ = 73379070971 is a prime.

It is a super-2 number, since 2×73412625403² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (73412425403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2823562503 + ... + 2823562528.

It is an arithmetic number, because the mean of its divisors is an integer number (19764937612).

Almost surely, 2^73412625403 is an apocalyptic number.

73412625403 is a deficient number, since it is larger than the sum of its proper divisors (5647125045).

73412625403 is a wasteful number, since it uses less digits than its factorization.

73412625403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5647125044.

The product of its (nonzero) digits is 120960, while the sum is 37.

The spelling of 73412625403 in words is "seventy-three billion, four hundred twelve million, six hundred twenty-five thousand, four hundred three".