Search a number
-
+
73701310525397 is a prime number
BaseRepresentation
bin10000110000011111101100…
…011011101110111111010101
3100122221202222001101000212022
4100300133230123232333111
534130010240443303042
6420425525321302525
721344513116012322
oct2060375433567725
9318852861330768
1073701310525397
1121535606447635
128323983934a45
133218008355549
14142b23bb23b49
1587c2183b0cd2
hex4307ec6eefd5

73701310525397 has 2 divisors, whose sum is σ = 73701310525398. Its totient is φ = 73701310525396.

The previous prime is 73701310525369. The next prime is 73701310525399. The reversal of 73701310525397 is 79352501310737.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61716877408081 + 11984433117316 = 7856009^2 + 3461854^2 .

It is a cyclic number.

It is not a de Polignac number, because 73701310525397 - 212 = 73701310521301 is a prime.

Together with 73701310525399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (73701310525399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36850655262698 + 36850655262699.

It is an arithmetic number, because the mean of its divisors is an integer number (36850655262699).

Almost surely, 273701310525397 is an apocalyptic number.

It is an amenable number.

73701310525397 is a deficient number, since it is larger than the sum of its proper divisors (1).

73701310525397 is an equidigital number, since it uses as much as digits as its factorization.

73701310525397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4167450, while the sum is 53.

The spelling of 73701310525397 in words is "seventy-three trillion, seven hundred one billion, three hundred ten million, five hundred twenty-five thousand, three hundred ninety-seven".