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7387560230117 is a prime number
BaseRepresentation
bin110101110000000110011…
…1001110011110011100101
3222011020120202220120011012
41223200030321303303211
51432014210404330432
623413444234152005
71361506425603434
oct153401471636345
928136522816135
107387560230117
11239905717a491
129b3912b82605
1341784a977992
141b77ba22311b
15cc279e59cb2
hex6b80ce73ce5

7387560230117 has 2 divisors, whose sum is σ = 7387560230118. Its totient is φ = 7387560230116.

The previous prime is 7387560230077. The next prime is 7387560230123. The reversal of 7387560230117 is 7110320657837.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6491330700481 + 896229529636 = 2547809^2 + 946694^2 .

It is an emirp because it is prime and its reverse (7110320657837) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7387560230117 - 212 = 7387560226021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7387560230317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3693780115058 + 3693780115059.

It is an arithmetic number, because the mean of its divisors is an integer number (3693780115059).

Almost surely, 27387560230117 is an apocalyptic number.

It is an amenable number.

7387560230117 is a deficient number, since it is larger than the sum of its proper divisors (1).

7387560230117 is an equidigital number, since it uses as much as digits as its factorization.

7387560230117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1481760, while the sum is 50.

The spelling of 7387560230117 in words is "seven trillion, three hundred eighty-seven billion, five hundred sixty million, two hundred thirty thousand, one hundred seventeen".