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74121232110131 is a prime number
BaseRepresentation
bin10000110110100110110001…
…101101011101001000110011
3100201102220212002220202120202
4100312212301231131020303
534203400240410011011
6421350453550225415
721420040141414313
oct2066466155351063
9321386762822522
1074121232110131
112168770220a448
1283912367b526b
1332487aa04453b
1414436b59d9443
158880e3bd623b
hex4369b1b5d233

74121232110131 has 2 divisors, whose sum is σ = 74121232110132. Its totient is φ = 74121232110130.

The previous prime is 74121232110127. The next prime is 74121232110169. The reversal of 74121232110131 is 13101123212147.

It is a weak prime.

It is an emirp because it is prime and its reverse (13101123212147) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 74121232110131 - 22 = 74121232110127 is a prime.

It is a super-2 number, since 2×741212321101312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 74121232110094 and 74121232110103.

It is not a weakly prime, because it can be changed into another prime (74121232110931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37060616055065 + 37060616055066.

It is an arithmetic number, because the mean of its divisors is an integer number (37060616055066).

Almost surely, 274121232110131 is an apocalyptic number.

74121232110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

74121232110131 is an equidigital number, since it uses as much as digits as its factorization.

74121232110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 74121232110131 its reverse (13101123212147), we get a palindrome (87222355322278).

The spelling of 74121232110131 in words is "seventy-four trillion, one hundred twenty-one billion, two hundred thirty-two million, one hundred ten thousand, one hundred thirty-one".