13101123212147 has 2 divisors, whose sum is σ = 13101123212148. Its totient is φ = 13101123212146.

The previous prime is 13101123212117. The next prime is 13101123212173. The reversal of 13101123212147 is 74121232110131.

It is a strong prime.

It is an emirp because it is prime and its reverse (74121232110131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101123212147 - 2²⁴ = 13101106434931 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101123212117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550561606073 + 6550561606074.

It is an arithmetic number, because the mean of its divisors is an integer number (6550561606074).

Almost surely, 2^{13101123212147} is an apocalyptic number.

13101123212147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101123212147 is an equidigital number, since it uses as much as digits as its factorization.

13101123212147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 13101123212147 its reverse (74121232110131), we get a palindrome (87222355322278).

The spelling of 13101123212147 in words is "thirteen trillion, one hundred one billion, one hundred twenty-three million, two hundred twelve thousand, one hundred forty-seven".