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74371670054117 is a prime number
BaseRepresentation
bin10000111010010000000000…
…111110011001010011100101
3100202022212021120002110220122
4100322100000332121103211
534222001140013212432
6422101512404411325
721444114213001562
oct2072200076312345
9322285246073818
1074371670054117
1121773936975477
1284118899a6b45
1332662aba6b787
14145187264b869
1588e8a01ab612
hex43a400f994e5

74371670054117 has 2 divisors, whose sum is σ = 74371670054118. Its totient is φ = 74371670054116.

The previous prime is 74371670054053. The next prime is 74371670054177. The reversal of 74371670054117 is 71145007617347.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56852414322916 + 17519255731201 = 7540054^2 + 4185601^2 .

It is an emirp because it is prime and its reverse (71145007617347) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 74371670054117 - 26 = 74371670054053 is a prime.

It is a super-2 number, since 2×743716700541172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (74371670054177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37185835027058 + 37185835027059.

It is an arithmetic number, because the mean of its divisors is an integer number (37185835027059).

Almost surely, 274371670054117 is an apocalyptic number.

It is an amenable number.

74371670054117 is a deficient number, since it is larger than the sum of its proper divisors (1).

74371670054117 is an equidigital number, since it uses as much as digits as its factorization.

74371670054117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3457440, while the sum is 53.

The spelling of 74371670054117 in words is "seventy-four trillion, three hundred seventy-one billion, six hundred seventy million, fifty-four thousand, one hundred seventeen".