Base | Representation |
---|---|
bin | 100010101001100101… |
… | …1011010110101000001 |
3 | 21010001202102221002222 |
4 | 1011103023122311001 |
5 | 2204342421241213 |
6 | 54103343220425 |
7 | 5242643052224 |
oct | 1052313326501 |
9 | 233052387088 |
10 | 74409946433 |
11 | 296145250a9 |
12 | 125078a7715 |
13 | 702ac80a04 |
14 | 385c59d5bb |
15 | 1e07861808 |
hex | 11532dad41 |
74409946433 has 2 divisors, whose sum is σ = 74409946434. Its totient is φ = 74409946432.
The previous prime is 74409946399. The next prime is 74409946451. The reversal of 74409946433 is 33464990447.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68046374449 + 6363571984 = 260857^2 + 79772^2 .
It is a cyclic number.
It is not a de Polignac number, because 74409946433 - 210 = 74409945409 is a prime.
It is not a weakly prime, because it can be changed into another prime (74409946493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37204973216 + 37204973217.
It is an arithmetic number, because the mean of its divisors is an integer number (37204973217).
Almost surely, 274409946433 is an apocalyptic number.
It is an amenable number.
74409946433 is a deficient number, since it is larger than the sum of its proper divisors (1).
74409946433 is an equidigital number, since it uses as much as digits as its factorization.
74409946433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7838208, while the sum is 53.
The spelling of 74409946433 in words is "seventy-four billion, four hundred nine million, nine hundred forty-six thousand, four hundred thirty-three".
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