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74944138481 is a prime number
BaseRepresentation
bin100010111001100000…
…1001100110011110001
321011102222121200211122
41011303001030303301
52211441144412411
654232344552025
75262120444362
oct1056301146361
9234388550748
1074944138481
1129869015533
1212636782615
1370b4847b94
1438ad4d5b69
151e396d09db
hex117304ccf1

74944138481 has 2 divisors, whose sum is σ = 74944138482. Its totient is φ = 74944138480.

The previous prime is 74944138429. The next prime is 74944138483. The reversal of 74944138481 is 18483144947.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51080068081 + 23864070400 = 226009^2 + 154480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-74944138481 is a prime.

It is a super-2 number, since 2×749441384812 (a number of 23 digits) contains 22 as substring.

Together with 74944138483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (74944138483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37472069240 + 37472069241.

It is an arithmetic number, because the mean of its divisors is an integer number (37472069241).

Almost surely, 274944138481 is an apocalyptic number.

It is an amenable number.

74944138481 is a deficient number, since it is larger than the sum of its proper divisors (1).

74944138481 is an equidigital number, since it uses as much as digits as its factorization.

74944138481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3096576, while the sum is 53.

The spelling of 74944138481 in words is "seventy-four billion, nine hundred forty-four million, one hundred thirty-eight thousand, four hundred eighty-one".