75001300501 has 2 divisors, whose sum is σ = 75001300502. Its totient is φ = 75001300500.

The previous prime is 75001300487. The next prime is 75001300531. The reversal of 75001300501 is 10500310057.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61690140625 + 13311159876 = 248375^2 + 115374^2 .

It is an emirp because it is prime and its reverse (10500310057) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 75001300501 - 2²³ = 74992911893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (75001300531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37500650250 + 37500650251.

It is an arithmetic number, because the mean of its divisors is an integer number (37500650251).

Almost surely, 2^75001300501 is an apocalyptic number.

It is an amenable number.

75001300501 is a deficient number, since it is larger than the sum of its proper divisors (1).

75001300501 is an equidigital number, since it uses as much as digits as its factorization.

75001300501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 525, while the sum is 22.

Adding to 75001300501 its reverse (10500310057), we get a palindrome (85501610558).

The spelling of 75001300501 in words is "seventy-five billion, one million, three hundred thousand, five hundred one".