75012121111001 has 2 divisors, whose sum is σ = 75012121111002. Its totient is φ = 75012121111000.

The previous prime is 75012121110893. The next prime is 75012121111003. The reversal of 75012121111001 is 10011112121057.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60778863366400 + 14233257744601 = 7796080^2 + 3772699^2 .

It is an emirp because it is prime and its reverse (10011112121057) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 75012121111001 - 2⁴⁶ = 4643376933337 is a prime.

It is a super-3 number, since 3×75012121111001³ (a number of 43 digits) contains 333 as substring.

Together with 75012121111003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (75012121111003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37506060555500 + 37506060555501.

It is an arithmetic number, because the mean of its divisors is an integer number (37506060555501).

Almost surely, 2^{75012121111001} is an apocalyptic number.

It is an amenable number.

75012121111001 is a deficient number, since it is larger than the sum of its proper divisors (1).

75012121111001 is an equidigital number, since it uses as much as digits as its factorization.

75012121111001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 140, while the sum is 23.

Adding to 75012121111001 its reverse (10011112121057), we get a palindrome (85023233232058).

The spelling of 75012121111001 in words is "seventy-five trillion, twelve billion, one hundred twenty-one million, one hundred eleven thousand, one".