7513237104493 has 2 divisors, whose sum is σ = 7513237104494. Its totient is φ = 7513237104492.

The previous prime is 7513237104491. The next prime is 7513237104511. The reversal of 7513237104493 is 3944017323157.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7003872269289 + 509364835204 = 2646483^2 + 713698^2 .

It is an emirp because it is prime and its reverse (3944017323157) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7513237104493 - 2¹ = 7513237104491 is a prime.

It is a super-3 number, since 3×7513237104493³ (a number of 40 digits) contains 333 as substring.

Together with 7513237104491, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7513237104491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3756618552246 + 3756618552247.

It is an arithmetic number, because the mean of its divisors is an integer number (3756618552247).

Almost surely, 2^{7513237104493} is an apocalyptic number.

It is an amenable number.

7513237104493 is a deficient number, since it is larger than the sum of its proper divisors (1).

7513237104493 is an equidigital number, since it uses as much as digits as its factorization.

7513237104493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1905120, while the sum is 49.

The spelling of 7513237104493 in words is "seven trillion, five hundred thirteen billion, two hundred thirty-seven million, one hundred four thousand, four hundred ninety-three".