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77025433765493 is a prime number
BaseRepresentation
bin10001100000110111100001…
…100111100100011001110101
3101002201120002220200220101102
4101200313201213210121311
540043441042020443433
6431452555030535445
722136622024240113
oct2140674147443165
9332646086626342
1077025433765493
11225a7337347974
128780065b07585
1333c960c69ccc5
14150409d8b8ab3
158d891ceea4e8
hex460de19e4675

77025433765493 has 2 divisors, whose sum is σ = 77025433765494. Its totient is φ = 77025433765492.

The previous prime is 77025433765453. The next prime is 77025433765499. The reversal of 77025433765493 is 39456733452077.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75412515985444 + 1612917780049 = 8684038^2 + 1270007^2 .

It is a cyclic number.

It is not a de Polignac number, because 77025433765493 - 218 = 77025433503349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (77025433765499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38512716882746 + 38512716882747.

It is an arithmetic number, because the mean of its divisors is an integer number (38512716882747).

Almost surely, 277025433765493 is an apocalyptic number.

It is an amenable number.

77025433765493 is a deficient number, since it is larger than the sum of its proper divisors (1).

77025433765493 is an equidigital number, since it uses as much as digits as its factorization.

77025433765493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 400075200, while the sum is 65.

The spelling of 77025433765493 in words is "seventy-seven trillion, twenty-five billion, four hundred thirty-three million, seven hundred sixty-five thousand, four hundred ninety-three".