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77754135853 is a prime number
BaseRepresentation
bin100100001101010000…
…0011111010100101101
321102200211010100120101
41020122200133110231
52233220024321403
655415244551101
75421551151502
oct1103240372455
9242624110511
1077754135853
112aa80201109
121309b852491
137441a65714
143a9879d4a9
15205124271d
hex121a81f52d

77754135853 has 2 divisors, whose sum is σ = 77754135854. Its totient is φ = 77754135852.

The previous prime is 77754135673. The next prime is 77754135863. The reversal of 77754135853 is 35853145777.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38983738249 + 38770397604 = 197443^2 + 196902^2 .

It is an emirp because it is prime and its reverse (35853145777) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-77754135853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 77754135794 and 77754135803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (77754135863) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38877067926 + 38877067927.

It is an arithmetic number, because the mean of its divisors is an integer number (38877067927).

Almost surely, 277754135853 is an apocalyptic number.

It is an amenable number.

77754135853 is a deficient number, since it is larger than the sum of its proper divisors (1).

77754135853 is an equidigital number, since it uses as much as digits as its factorization.

77754135853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12348000, while the sum is 55.

The spelling of 77754135853 in words is "seventy-seven billion, seven hundred fifty-four million, one hundred thirty-five thousand, eight hundred fifty-three".