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7906132510853 is a prime number
BaseRepresentation
bin111001100001100101000…
…1110000100100010000101
31000222211002222010220000012
41303003022032010202011
52014013224410321403
624452005510000005
71444125222345143
oct163031216044205
930884088126005
107906132510853
112578a76765325
12a78317946005
13454711767a85
141d4931c82593
15da9cb2daed8
hex730ca384885

7906132510853 has 2 divisors, whose sum is σ = 7906132510854. Its totient is φ = 7906132510852.

The previous prime is 7906132510819. The next prime is 7906132510883. The reversal of 7906132510853 is 3580152316097.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4854099052804 + 3052033458049 = 2203202^2 + 1747007^2 .

It is a cyclic number.

It is not a de Polignac number, because 7906132510853 - 28 = 7906132510597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7906132510883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3953066255426 + 3953066255427.

It is an arithmetic number, because the mean of its divisors is an integer number (3953066255427).

Almost surely, 27906132510853 is an apocalyptic number.

It is an amenable number.

7906132510853 is a deficient number, since it is larger than the sum of its proper divisors (1).

7906132510853 is an equidigital number, since it uses as much as digits as its factorization.

7906132510853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The spelling of 7906132510853 in words is "seven trillion, nine hundred six billion, one hundred thirty-two million, five hundred ten thousand, eight hundred fifty-three".