Base | Representation |
---|---|
bin | 100101010111001011… |
… | …1001011111111100111 |
3 | 21200002200210100122111 |
4 | 1022232113023333213 |
5 | 2303310042202401 |
6 | 100505340341451 |
7 | 5540201625034 |
oct | 1125627137747 |
9 | 250080710574 |
10 | 80234725351 |
11 | 31033457780 |
12 | 13672544887 |
13 | 7748959b61 |
14 | 3c51dda38b |
15 | 2148dd6e51 |
hex | 12ae5cbfe7 |
80234725351 has 4 divisors (see below), whose sum is σ = 87528791304. Its totient is φ = 72940659400.
The previous prime is 80234725327. The next prime is 80234725381. The reversal of 80234725351 is 15352743208.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80234725351 is a prime.
It is a super-2 number, since 2×802347253512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (80234725381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3647032960 + ... + 3647032981.
It is an arithmetic number, because the mean of its divisors is an integer number (21882197826).
Almost surely, 280234725351 is an apocalyptic number.
80234725351 is a deficient number, since it is larger than the sum of its proper divisors (7294065953).
80234725351 is a wasteful number, since it uses less digits than its factorization.
80234725351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7294065952.
The product of its (nonzero) digits is 201600, while the sum is 40.
It can be divided in two parts, 8023 and 4725351, that added together give a palindrome (4733374).
The spelling of 80234725351 in words is "eighty billion, two hundred thirty-four million, seven hundred twenty-five thousand, three hundred fifty-one".
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