Base | Representation |
---|---|
bin | 10010010010000101010001… |
… | …100010100000000001111011 |
3 | 101112200212200111022120001111 |
4 | 102102011101202200001323 |
5 | 41014343424342401003 |
6 | 443002401204101151 |
7 | 22636150405250662 |
oct | 2222052142400173 |
9 | 345625614276044 |
10 | 80407450747003 |
11 | 23690676801a96 |
12 | 90276046947b7 |
13 | 35b350bca51a3 |
14 | 15bda544c7dd9 |
15 | 9468b04d5e6d |
hex | 4921518a007b |
80407450747003 has 2 divisors, whose sum is σ = 80407450747004. Its totient is φ = 80407450747002.
The previous prime is 80407450746967. The next prime is 80407450747067. The reversal of 80407450747003 is 30074705470408.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 80407450747003 - 221 = 80407448649851 is a prime.
It is not a weakly prime, because it can be changed into another prime (80407450717003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40203725373501 + 40203725373502.
It is an arithmetic number, because the mean of its divisors is an integer number (40203725373502).
Almost surely, 280407450747003 is an apocalyptic number.
80407450747003 is a deficient number, since it is larger than the sum of its proper divisors (1).
80407450747003 is an equidigital number, since it uses as much as digits as its factorization.
80407450747003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2634240, while the sum is 49.
The spelling of 80407450747003 in words is "eighty trillion, four hundred seven billion, four hundred fifty million, seven hundred forty-seven thousand, three".
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