Base | Representation |
---|---|
bin | 111010110000110100001… |
… | …0101000101111001100101 |
3 | 1001121002022110100211222011 |
4 | 1311201220111011321211 |
5 | 2024310214423014013 |
6 | 25102110151234221 |
7 | 1462330652523562 |
oct | 165415025057145 |
9 | 31532273324864 |
10 | 8076288876133 |
11 | 2634153581aa5 |
12 | aa52a4978971 |
13 | 46778ac0c09a |
14 | 1dcc745bd869 |
15 | e0139721c3d |
hex | 75868545e65 |
8076288876133 has 2 divisors, whose sum is σ = 8076288876134. Its totient is φ = 8076288876132.
The previous prime is 8076288876109. The next prime is 8076288876157. The reversal of 8076288876133 is 3316788826708.
It is a balanced prime because it is at equal distance from previous prime (8076288876109) and next prime (8076288876157).
It can be written as a sum of positive squares in only one way, i.e., 7943925339009 + 132363537124 = 2818497^2 + 363818^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8076288876133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8076288876193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4038144438066 + 4038144438067.
It is an arithmetic number, because the mean of its divisors is an integer number (4038144438067).
Almost surely, 28076288876133 is an apocalyptic number.
It is an amenable number.
8076288876133 is a deficient number, since it is larger than the sum of its proper divisors (1).
8076288876133 is an equidigital number, since it uses as much as digits as its factorization.
8076288876133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 130056192, while the sum is 67.
The spelling of 8076288876133 in words is "eight trillion, seventy-six billion, two hundred eighty-eight million, eight hundred seventy-six thousand, one hundred thirty-three".
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