Base | Representation |
---|---|
bin | 10111100011111000101… |
… | …10101010101010010111 |
3 | 2212101120020122111122220 |
4 | 23301330112222222113 |
5 | 101230414240341333 |
6 | 1415521515153423 |
7 | 112326105615624 |
oct | 13617426525227 |
9 | 2771506574586 |
10 | 809540168343 |
11 | 292362358445 |
12 | 110a89445873 |
13 | 5b4546070ba |
14 | 2b2793cb34b |
15 | 160d0b1d8b3 |
hex | bc7c5aaa97 |
809540168343 has 4 divisors (see below), whose sum is σ = 1079386891128. Its totient is φ = 539693445560.
The previous prime is 809540168321. The next prime is 809540168357. The reversal of 809540168343 is 343861045908.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 809540168343 - 29 = 809540167831 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (809540168303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134923361388 + ... + 134923361393.
It is an arithmetic number, because the mean of its divisors is an integer number (269846722782).
Almost surely, 2809540168343 is an apocalyptic number.
809540168343 is a deficient number, since it is larger than the sum of its proper divisors (269846722785).
809540168343 is a wasteful number, since it uses less digits than its factorization.
809540168343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 269846722784.
The product of its (nonzero) digits is 2488320, while the sum is 51.
The spelling of 809540168343 in words is "eight hundred nine billion, five hundred forty million, one hundred sixty-eight thousand, three hundred forty-three".
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