Base | Representation |
---|---|
bin | 1111000101100110… |
… | …00011000100010001 |
3 | 202220111120122010122 |
4 | 13202303003010101 |
5 | 113042100000032 |
6 | 3415431040025 |
7 | 404503602254 |
oct | 74263030421 |
9 | 22814518118 |
10 | 8100000017 |
11 | 348726999a |
12 | 16a0810015 |
13 | 9c1186925 |
14 | 56ba9909b |
15 | 3261a0012 |
hex | 1e2cc3111 |
8100000017 has 4 divisors (see below), whose sum is σ = 8252830260. Its totient is φ = 7947169776.
The previous prime is 8099999993. The next prime is 8100000023. The reversal of 8100000017 is 7100000018.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7100000018 = 2 ⋅3550000009.
It can be written as a sum of positive squares in 2 ways, for example, as 4668852241 + 3431147776 = 68329^2 + 58576^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8100000017 is a prime.
It is a super-2 number, since 2×81000000172 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 8099999950 and 8100000004.
It is not an unprimeable number, because it can be changed into a prime (8100000917) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76415042 + ... + 76415147.
It is an arithmetic number, because the mean of its divisors is an integer number (2063207565).
Almost surely, 28100000017 is an apocalyptic number.
It is an amenable number.
8100000017 is a deficient number, since it is larger than the sum of its proper divisors (152830243).
8100000017 is a wasteful number, since it uses less digits than its factorization.
8100000017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152830242.
The product of its (nonzero) digits is 56, while the sum is 17.
The square root of 8100000017 is about 90000.0000944444. Note that the first 4 decimals coincide. The cubic root of 8100000017 is about 2008.2988516515.
Subtracting from 8100000017 its sum of digits (17), we obtain a 4-th power (8100000000 = 3004).
Subtracting from 8100000017 its reverse (7100000018), we obtain a palindrome (999999999).
The spelling of 8100000017 in words is "eight billion, one hundred million, seventeen", and thus it is an aban number.
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