8100000023 has 2 divisors, whose sum is σ = 8100000024. Its totient is φ = 8100000022.

The previous prime is 8099999993. The next prime is 8100000053. The reversal of 8100000023 is 3200000018.

It is a balanced prime because it is at equal distance from previous prime (8099999993) and next prime (8100000053).

It is a cyclic number.

It is not a de Polignac number, because 8100000023 - 2¹² = 8099995927 is a prime.

It is a super-2 number, since 2×8100000023² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 8099999953 and 8100000007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8100000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4050000011 + 4050000012.

It is an arithmetic number, because the mean of its divisors is an integer number (4050000012).

Almost surely, 2^8100000023 is an apocalyptic number.

8100000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

8100000023 is an equidigital number, since it uses as much as digits as its factorization.

8100000023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 8100000023 is about 90000.0001277778. Note that the first 3 decimals coincide. The cubic root of 8100000023 is about 2008.2988521474.

The spelling of 8100000023 in words is "eight billion, one hundred million, twenty-three", and thus it is an aban number.