8100000019 has 4 divisors (see below), whose sum is σ = 8100320800. Its totient is φ = 8099679240.

The previous prime is 8099999993. The next prime is 8100000023. The reversal of 8100000019 is 9100000018.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 9100000018 = 2 ⋅4550000009.

It is a cyclic number.

It is not a de Polignac number, because 8100000019 - 2⁵ = 8099999987 is a prime.

It is a super-2 number, since 2×8100000019² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 8099999951 and 8100000005.

It is not an unprimeable number, because it can be changed into a prime (8100000079) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118944 + ... + 174205.

It is an arithmetic number, because the mean of its divisors is an integer number (2025080200).

Almost surely, 2^8100000019 is an apocalyptic number.

8100000019 is a deficient number, since it is larger than the sum of its proper divisors (320781).

8100000019 is a wasteful number, since it uses less digits than its factorization.

8100000019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320780.

The product of its (nonzero) digits is 72, while the sum is 19.

The square root of 8100000019 is about 90000.0001055556. Note that the first 3 decimals coincide. The cubic root of 8100000019 is about 2008.2988518168.

Subtracting from 8100000019 its sum of digits (19), we obtain a 4-th power (8100000000 = 300⁴).

Subtracting 8100000019 from its reverse (9100000018), we obtain a palindrome (999999999).

The spelling of 8100000019 in words is "eight billion, one hundred million, nineteen", and thus it is an aban number.