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81126000133 is a prime number
BaseRepresentation
bin100101110001101111…
…1001000011000000101
321202101210212210210121
41023203133020120011
52312121224001013
6101134015421541
75601243423553
oct1134337103005
9252353783717
1081126000133
113145056a702
1213880b248b1
13785b4b9c99
143cd8524bd3
15219c28d58d
hex12e37c8605

81126000133 has 2 divisors, whose sum is σ = 81126000134. Its totient is φ = 81126000132.

The previous prime is 81126000127. The next prime is 81126000161. The reversal of 81126000133 is 33100062118.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58788306369 + 22337693764 = 242463^2 + 149458^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-81126000133 is a prime.

It is a super-3 number, since 3×811260001333 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 81126000098 and 81126000107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (81126000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40563000066 + 40563000067.

It is an arithmetic number, because the mean of its divisors is an integer number (40563000067).

Almost surely, 281126000133 is an apocalyptic number.

It is an amenable number.

81126000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

81126000133 is an equidigital number, since it uses as much as digits as its factorization.

81126000133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

The spelling of 81126000133 in words is "eighty-one billion, one hundred twenty-six million, one hundred thirty-three", and thus it is an aban number.