Base | Representation |
---|---|
bin | 100101110001110010… |
… | …1101011100100011111 |
3 | 21202101221010001002212 |
4 | 1023203211223210133 |
5 | 2312122143422101 |
6 | 101134120311035 |
7 | 5601264134465 |
oct | 1134345534437 |
9 | 252357101085 |
10 | 81127717151 |
11 | 31451532728 |
12 | 1388161247b |
13 | 785b96b680 |
14 | 3cd8850835 |
15 | 219c4cc1bb |
hex | 12e396b91f |
81127717151 has 4 divisors (see below), whose sum is σ = 87368310792. Its totient is φ = 74887123512.
The previous prime is 81127717063. The next prime is 81127717159. The reversal of 81127717151 is 15171772118.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-81127717151 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 81127717099 and 81127717108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (81127717159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3120296801 + ... + 3120296826.
It is an arithmetic number, because the mean of its divisors is an integer number (21842077698).
Almost surely, 281127717151 is an apocalyptic number.
81127717151 is a deficient number, since it is larger than the sum of its proper divisors (6240593641).
81127717151 is a wasteful number, since it uses less digits than its factorization.
81127717151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6240593640.
The product of its digits is 27440, while the sum is 41.
The spelling of 81127717151 in words is "eighty-one billion, one hundred twenty-seven million, seven hundred seventeen thousand, one hundred fifty-one".
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