81140992141 has 4 divisors (see below), whose sum is σ = 88517445984. Its totient is φ = 73764538300.

The previous prime is 81140992123. The next prime is 81140992151. The reversal of 81140992141 is 14129904118.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 81140992141 - 2¹⁵ = 81140959373 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 81140992094 and 81140992103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (81140992111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3688226905 + ... + 3688226926.

It is an arithmetic number, because the mean of its divisors is an integer number (22129361496).

Almost surely, 2^81140992141 is an apocalyptic number.

It is an amenable number.

81140992141 is a deficient number, since it is larger than the sum of its proper divisors (7376453843).

81140992141 is a wasteful number, since it uses less digits than its factorization.

81140992141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7376453842.

The product of its (nonzero) digits is 20736, while the sum is 40.

The spelling of 81140992141 in words is "eighty-one billion, one hundred forty million, nine hundred ninety-two thousand, one hundred forty-one".