Base | Representation |
---|---|
bin | 10111100111111000110… |
… | …00001111100001111001 |
3 | 2212121002221021222011022 |
4 | 23303330120033201321 |
5 | 101244314121041040 |
6 | 1420515004112225 |
7 | 112433246500466 |
oct | 13637430174171 |
9 | 2777087258138 |
10 | 811688065145 |
11 | 293264830071 |
12 | 111388835675 |
13 | 5b7075c4c59 |
14 | 2b40078466d |
15 | 161a94976b5 |
hex | bcfc60f879 |
811688065145 has 4 divisors (see below), whose sum is σ = 974025678180. Its totient is φ = 649350452112.
The previous prime is 811688065129. The next prime is 811688065159. The reversal of 811688065145 is 541560886118.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 589246605376 + 222441459769 = 767624^2 + 471637^2 .
It is a cyclic number.
It is not a de Polignac number, because 811688065145 - 24 = 811688065129 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81168806510 + ... + 81168806519.
It is an arithmetic number, because the mean of its divisors is an integer number (243506419545).
Almost surely, 2811688065145 is an apocalyptic number.
It is an amenable number.
811688065145 is a deficient number, since it is larger than the sum of its proper divisors (162337613035).
811688065145 is a wasteful number, since it uses less digits than its factorization.
811688065145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162337613034.
The product of its (nonzero) digits is 1843200, while the sum is 53.
The spelling of 811688065145 in words is "eight hundred eleven billion, six hundred eighty-eight million, sixty-five thousand, one hundred forty-five".
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