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8143811343359 = 26930274391611
BaseRepresentation
bin111011010000010000011…
…1110110111001111111111
31001211112121012210120210122
41312200200332313033333
52031412011200441414
625153114300125155
71500241144160606
oct166404076671777
931745535716718
108143811343359
11265a85321601a
12ab63a9b367bb
13470c5bc926c3
1420223c152a3d
15e1c8c593b8e
hex76820fb73ff

8143811343359 has 4 divisors (see below), whose sum is σ = 8174085735240. Its totient is φ = 8113536951480.

The previous prime is 8143811343313. The next prime is 8143811343361. The reversal of 8143811343359 is 9533431183418.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-8143811343359 is a prime.

It is a super-3 number, since 3×81438113433593 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 8143811343359.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (8143811343259) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15137195537 + ... + 15137196074.

It is an arithmetic number, because the mean of its divisors is an integer number (2043521433810).

Almost surely, 28143811343359 is an apocalyptic number.

8143811343359 is a deficient number, since it is larger than the sum of its proper divisors (30274391881).

8143811343359 is a wasteful number, since it uses less digits than its factorization.

8143811343359 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30274391880.

The product of its digits is 3732480, while the sum is 53.

The spelling of 8143811343359 in words is "eight trillion, one hundred forty-three billion, eight hundred eleven million, three hundred forty-three thousand, three hundred fifty-nine".

Divisors: 1 269 30274391611 8143811343359